If 22 0 Ml Of 0 182 M Naoh Solution Is Added To 100 Ml Of Solution Which Is 0 10 (1)
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Do my questionIf 22.0 mL of 0.182 M NaOH solution is added to 100. mL of solution which is 0.100 M in HA (Ka = 5.00×10−5) and 0.100 M in NaA, what will be the pH of the new solution?
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